2(^-3+x)=16^x

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Solution for 2(^-3+x)=16^x equation: 



2(^-3+x)=16^x

We move all terms to the left:

2(^-3+x)-(16^x)=0

We multiply parentheses

2x-16^x-6+=0

We add all the numbers together, and all the variables

2x-16^x=0

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